To find the \( n \)th term of a quadratic sequence, we aim for a formula in the form:
\[ a_n = an^2 + bn + c \]
Here’s a step-by-step method using an example:
Consider the sequence:
\[ 10, 24, 44, 70, 102 \]
Find the first differences (subtract each term from the next):
\[ 24 – 10 = 14, \quad 44 – 24 = 20, \quad 70 – 44 = 26, \quad 102 – 70 = 32 \]
The first differences are: \( 14, 20, 26, 32 \).
Now, find the second differences (subtract each first difference from the next):
\[ 20 – 14 = 6, \quad 26 – 20 = 6, \quad 32 – 26 = 6 \]
The second differences are constant (\( 6 \)), confirming this is a quadratic sequence.
Halve the second difference to find the coefficient of \( n^2 \):
\[ a = \frac{6}{2} = 3 \]
So the \( n^2 \)-term is \( 3n^2 \).
Subtract \( 3n^2 \) from each term of the sequence to create a new sequence. For \( 10, 24, 44, 70, 102 \):
\[ 10 – 3(1^2) = 7, \quad 24 – 3(2^2) = 12, \quad 44 – 3(3^2) = 17, \quad 70 – 3(4^2) = 22, \quad 102 – 3(5^2) = 27 \]
The new sequence is \( 7, 12, 17, 22, 27 \).
The new sequence \( 7, 12, 17, 22, 27 \) is an arithmetic sequence with a common difference of \( 5 \) and a 0th term of \( 2 \). Its formula is:
\[ 5n + 2 \]
The quadratic \( n \)th term is the sum of \( 3n^2 \) and \( 5n + 2 \):
\[ a_n = 3n^2 + 5n + 2 \]
You can use this formula to find any term in the sequence. For example, to find the 4th term (\( a_4 \)):
\[ a_4 = 3(4^2) + 5(4) + 2 = 3(16) + 20 + 2 = 48 + 20 + 2 = 70 \]
The 4th term is 70.
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