Direct proportion describes a relationship where two quantities increase or decrease at the same rate. If one quantity is multiplied or divided by a factor, the other quantity is multiplied or divided by the same factor. This concept is widely used in real-life scenarios such as finding the best value for money, scaling recipes, and converting currencies.
In direct proportion, the relationship between two variables can be expressed as:
\[ y = kx \]
Here, \(k\) is the constant of proportionality. If you know one variable and the constant, you can calculate the other.
To determine the best buy, compare the unit prices of items. The unit price is calculated by dividing the total cost by the quantity.
\[ \text{Unit price} = \frac{\text{Total cost}}{\text{Quantity}} \]
Example: You are comparing two brands of rice:
Calculate the unit prices:
Brand B offers better value as its unit price is lower.
To scale a recipe, multiply or divide the ingredients by the same factor as the change in the number of servings.
Example: A recipe for 4 servings requires 200 g of flour. You need enough for 6 servings. Use direct proportion:
\[ \text{New quantity} = \frac{\text{Required servings}}{\text{Original servings}} \times \text{Original quantity} \]
Substitute the values:
\[ \text{New quantity} = \frac{6}{4} \times 200 = 1.5 \times 200 = 300 \, \text{g} \]
You will need 300 g of flour for 6 servings.
Direct proportion is used to convert between currencies. Multiply or divide by the exchange rate to find the equivalent amount.
Example: The exchange rate is £1 = €1.15. How many euros can you get for £50?
\[ \text{Euros} = \text{Pounds} \times \text{Exchange rate} \]
Substitute the values:
\[ \text{Euros} = 50 \times 1.15 = 57.50 \]
You can get €57.50 for £50.
Reverse conversion: To convert €80 back to pounds, divide by the exchange rate:
\[ \text{Pounds} = \frac{\text{Euros}}{\text{Exchange rate}} = \frac{80}{1.15} = 69.57 \, \text{(rounded to 2 decimal places)} \]
Direct proportion is a versatile concept used to solve real-world problems efficiently.
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