Completing the square involves collecting the \( x^2\) and \( x\) terms together in a bracket which can be quicker than using the quadratic formula to solve a quadratic equation.
The method of completing the square can be streamlined by using the formula:
\[ x^2 + bx = \left(x – \frac{b}{2}\right)^2 – \left(\frac{b}{2}\right)^2 \]
This formula allows you to rewrite the quadratic equation into a form that is easier to solve while keeping the equation balanced.
To solve a quadratic equation using this formula, follow these steps:
The coefficient of \( x^2 \) is already 1, so no adjustment is needed.
For \( x^2 + 6x \), the formula gives: \[ x^2 + 6x = \left(x – \frac{6}{2}\right)^2 – \left(\frac{6}{2}\right)^2 \] \[ x^2 + 6x = (x – 3)^2 – 9 \]
Replace \( x^2 + 6x \) in the original equation \( x^2 + 6x + 5 = 0 \): \[ (x – 3)^2 – 9 + 5 = 0 \]
Simplify: \[ (x – 3)^2 – 4 = 0 \]
Isolate the perfect square: \[ (x – 3)^2 = 4 \]
Take the square root of both sides: \[ x – 3 = \pm \sqrt{4} \] \[ x – 3 = \pm 2 \]
Isolate \( x \): \[ x = 3 + 2 \quad \text{or} \quad x = 3 – 2 \] \[ x = 5 \quad \text{or} \quad x = 1 \]
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