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DATA

NEXUS

- EDEXCEL GCSE
- AQA GCSE
- OCR GCSE
- EDUQAS GCSE

To solve equations, you need to be careful of the order you do it. Deal with the plus and minuses first, then deal with the multiplications and divisions.

\[2x+3=11\]

We must deal with the \(+3\) first. The inverse (or opposite) of \(+3\) is \(-3\). We **must **do this to both sides though.

\[2x+3-3=11-3\]

\[2x=8\]

The inverse (or opposite) of \(\times 2\) is \(\div 2\).

\[2x \div 2=8 \div 2\]

\[x=4\]

\[\frac{x}{5}-2=3\]

We must deal with the \(-2\) first. The inverse (or opposite) of \(-2\) is \(+2\).

\[\frac{x}{5}-2+2=3+2\]

\[\frac{x}{5}=5\]

The inverse (or opposite) of \(\div 5\) is \(\times 5\).

\[\frac{x}{5} \times 5=5 \times 5\]

\[x=25\]

\[\frac{x+2}{3}=10\]

It may be tempting to deal with the \(+2\) first, but it is trapped inside a fraction. We **must** always deal with brackets and fractions first.

\[\frac{x+2}{3}\times 3=10 \times 3\]

\[x+2=30\]

\[x+2-2=30-2\]

\[x=28\]

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