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1
The following iteration formulae can be used to find solutions to quadratic equations.
Select which can be used to solve:
1
Q1 Tutorial2
The following iteration formulae can be used to find solutions to quadratic equations.
Select which can be used to solve:
1
3
The following iteration formulae can be used to find solutions to quadratic equations.
Select which can be used to solve:
1
4
Use the iterative formula:
xn+1 = - √x with x0 = 2
to find the solution to f(x) correct to 2 decimal places.
xn+1 = - √x with x0 = 2
to find the solution to f(x) correct to 2 decimal places.
| xn | Solution |
| x0 = | 2 |
| x1 = | |
| x2 = | |
| x3 = | |
| x4 = | |
| x5 = | |
| x6 = | |
| x7 = |
x =
3
5
Use the iterative formula:
xn+1 = - √x with x0 = 2
to find the solution to f(x) correct to 2 decimal places.
xn+1 = - √x with x0 = 2
to find the solution to f(x) correct to 2 decimal places.
| xn | Solution |
| x0 = | 2 |
| x1 = | |
| x2 = | |
| x3 = | |
| x4 = | |
| x5 = | |
| x6 = | |
| x7 = |
x =
3
6
Use the iterative formula:
xn+1 = - √x with x0 = 2
to find the solution to f(x) correct to 2 decimal places.
xn+1 = - √x with x0 = 2
to find the solution to f(x) correct to 2 decimal places.
| xn | Solution |
| x0 = | 2 |
| x1 = | |
| x2 = | |
| x3 = | |
| x4 = | |
| x5 = | |
| x6 = | |
| x7 = |
x =
3
7
Use the iterative formula:
xn+1 = 3√x + with x0 = 1
to find the solution to f(x) correct to 3 decimal places.
xn+1 = 3√x + with x0 = 1
to find the solution to f(x) correct to 3 decimal places.
| xn | Solution |
| x0 = | 1 |
| x1 = | |
| x2 = | |
| x3 = | |
| x4 = | |
| x5 = | |
| x6 = | |
| x7 = |
x =
3
8
Use the iterative formula:
xn+1 = 3√x + with x0 = 1
to find the solution to f(x) correct to 3 decimal places.
xn+1 = 3√x + with x0 = 1
to find the solution to f(x) correct to 3 decimal places.
| xn | Solution |
| x0 = | 1 |
| x1 = | |
| x2 = | |
| x3 = | |
| x4 = | |
| x5 = | |
| x6 = | |
| x7 = |
x =
3
9
Use the iterative formula:
xn+1 = 3√x + with x0 = 1
to find the solution to f(x) correct to 3 decimal places.
xn+1 = 3√x + with x0 = 1
to find the solution to f(x) correct to 3 decimal places.
| xn | Solution |
| x0 = | 1 |
| x1 = | |
| x2 = | |
| x3 = | |
| x4 = | |
| x5 = | |
| x6 = | |
| x7 = |
x =
3
